Printing after typecasting with %d or %i gives unexpected outputs

I am rounding off some values and then printing them. When I use %f option, they are printed correctly, but using the %d or %i option (even after casting the rounded values to int) is giving a weird output, and I am not able to figure the why of it out.

Any help is much appreciated!

When I use %f:

i = 0;

while(i < n_shapes)
{
    ll_x[i] = (int)round((ll_x[i] - min_x)/pitch_x);
    ll_y[i] = (int)round((ll_y[i] - min_y)/pitch_y);
    ur_x[i] = (int)round((ur_x[i] - min_x)/pitch_x);
    ur_y[i] = (int)round((ur_y[i] - min_y)/pitch_y);
    printf("%f,%f,%f,%f\n", ll_x[i], ll_y[i], ur_x[i], ur_y[i]);
    i++;
}

Output:

115.000000,94.000000,115.000000,101.000000
116.000000,51.000000,117.000000,58.000000
116.000000,60.000000,117.000000,67.000000
116.000000,69.000000,117.000000,75.000000
116.000000,77.000000,117.000000,84.000000
116.000000,86.000000,117.000000,93.000000
116.000000,94.000000,117.000000,101.000000

Now, with %d (or %i):

i = 0;

while(i < n_shapes)
{
    ll_x[i] = (int)round((ll_x[i] - min_x)/pitch_x);
    ll_y[i] = (int)round((ll_y[i] - min_y)/pitch_y);
    ur_x[i] = (int)round((ur_x[i] - min_x)/pitch_x);
    ur_y[i] = (int)round((ur_y[i] - min_y)/pitch_y);
    printf("%d,%d,%d,%d\n", ll_x[i], ll_y[i], ur_x[i], ur_y[i]);
    i++;
}

Output:

1079590912,0,6,-1
1078788096,0,5,-1
1079033856,0,6,-1
1079164928,0,6,-1
1079312384,0,6,-1
1079459840,0,6,-1
1079590912,0,6,-1

Thank you!

Edit: Yes, I realize that using (int) in the printf gives me the right output. I was curious about the values I got when I didn't do so. What does my output when I use %d without casting inside the printf mean?